Atomic number of Ag is 47. ln the same group, the atomic number of elements placed above and below Ag will be:

Atomic number of Ag is 47. ln the same group, the atomic number of elements placed above and below Ag will be 29, 79.

Ag with atomic number 47 is present in the d−block. Element above Ag is  Cu having atomic number 29.

Element below Ag is Au having atomic number 79.

$\mathrm{Cu}\Rightarrow 47-18=29;\mathrm{Au}\Rightarrow 47+32=79$.

Hence, the option B is correct.