Based on acetic acid Ka∘=1.8×10−5 solution,The concentration of H+ in 0.05 M acetic acid solution is - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
$4.5 \times 10^{- 3} M$
B
$9.5 \times 10^{- 3} M$
C
$4.5 \times 10^{- 4} M$
D
$9.5 \times 10^{- 4} M$

Solution:

$[H^{+}] = c α = (0.05 M) (0.019) = 9.5 \times 10^{- 4} M$

The concentration of $H^{+}$ in 0.05 M acetic acid solution is $9.5 \times 10^{- 4} M$

Since pH is the logarithm of the reciprocal of the hydrogen ion concentration in grime moles per liter, it is a more practical way to represent hydrogen ion concentration.

Based on acetic acid $(K_{a}^{\circ} = 1.8 \times 10^{- 5})$ solution,
The concentration of $H^{+}$ in 0.05 M acetic acid solution is

Solution:

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