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Calculate the total number of electron for $F e$ having $n + l + m = 2$ .

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Correct option is C

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} n \to 1 2 2 3 3 4 3 l \to 0 0 1 0 1 0 2 m \to 0 0 - 1 0 - 1 0 - 2 0 0 - 1 + 1 + 1 1 2$

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Calculate the total number of electron for Fe having n+l+m=2.