Calculate the total number of electron for Fe having n+l+m=2.

  1. A

    2

  2. B

    3

  3. C

    4

  4. D

    1

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    Solution:

             1s2  2s2  2p6  3s2  3p6  4s2  3d10 n  1      2       2      3      3       4     3 l   0      0       1      0      1       0     2 m 0     0     -1     0     -1    0    -2                            0               0            -1                         +1             +1            1                                                               2

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