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$C_{n} H_{2 n + 2} O$ is the general formula of ethers.
To exhibit the functional group isomerism ‘n’ must be minimum.

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detailed solution

Correct option is B

Simple formula of ether is ${CH}_{3} - O - {CH}_{3}$ . So, the value of n is 2 where we have two isomers:

$C_{2} H_{2 \times 2 + 2} O = C_{2} H_{6} O (n = 2) Isomers : C_{2} H_{5} OH, {CH}_{3} - O - {CH}_{3}$

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detailed solution

Correct answer is 2

Simple formula of ether is ${CH}_{3} - O - {CH}_{3}$ . So, the value of n is 2 where we have two isomers:

$C_{2} H_{2 \times 2 + 2} O = C_{2} H_{6} O (n = 2) Isomers : C_{2} H_{5} OH, {CH}_{3} - O - {CH}_{3}$

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CnH2n+2O is the general formula of ethers. To exhibit the functional group isomerism ‘n’ must be minimum.