Questions

column I column II
(a) No. of electrons in Na (11) having m = 0 (p) 7
(b) No. of electrons in S (16) having $(n + l) = 3$ (q) 15
(c)
No. of maximum possible electrons having
$s = + \frac{1}{2}$ spin in $Cr (24)$
(r) 8
(s) 12

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(a - p); (b - r); (c - q)

(a - q); (b - r); (c - p)

(a - r); (b - p); (c - q)

(a - p); (b - p); (c - r)

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detailed solution

Correct option is A

2 from 1s, 2 from 2s, 2 from 2p, and 1 from 3s add up to 7 electrons when m = 0 in the sodium atom.

Now we have,

$_{16} S = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}$

Here $n + l = 3$ for $2 p^{6}$ and $3 s^{2}$ electrons which is for 8 electrons.

The transition metal chromium has an atomic number of 24. No. of maximum possible electrons When the value of s is positive 1/2, it equals 15 in.

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	column I	column II
(a)	No. of electrons in Na (11) having m = 0	(p)	7
(b)	No. of electrons in S (16) having $(n + l) = 3$	(q)	15
(c)	No. of maximum possible electrons having $s = + \frac{1}{2}$ spin in $Cr (24)$	(r)	8
		(s)	12

column Icolumn II (a)No. of electrons in Na (11) having m = 0(p)7(b)No. of electrons in S (16) having (n + l) =3(q)15(c)No. of maximum possible electrons having s=+12 spin in Cr(24)(r)8 (s)12