Energy of a photon with a wavelength of 450 nm is

Energy of a photon with a wavelength of 450 nm is

A
$4.36 \times 10^{- 12} ergs$
B
$4.36 \times 10^{- 13} ergs$
C
$4.36 \times 10^{- 20} ergs$
D
$4.36 \times 10^{- 11} ergs$

Solution:

According to Max Planck’s equation,

$E = \frac{hc}{λ} \to eqn (1)$

Here h is Planck’s constant and c is speed of light.

The wave length of photon $λ$ = 450nm

$h = 6.625 \times 10^{- 27} ergs . \sec$

$c = 3 \times 10^{10} cm / \sec$

From equation 1, the energy of photon is

$E = \frac{6.625 \times 10^{- 27} ergs . \sec \times 3 \times 10^{10} cm . \sec^{- 1}}{450 \times 10^{- 7} cm}$ $∴ E = 4.36 \times 10^{- 12} ergs$

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