Enthalpies of formation of ethane, ethyene and benzene from the gaseous atoms are $- 2839.2$ , $- 2275.2$ and $- 5536 kJ {mol}^{- 1}$ , respectively. Bond enthalpy of C-H is $410.87 kJ {mol}^{- 1}$ . Resonance energy of benzene is

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$- 243.59 kJ {mol}^{- 1}$

$- 23.4 kJ {mol}^{- 1}$

$- 156.84 kJ {mol}^{- 1}$

$- 53.68 kJ {mol}^{- 1}$

answer is D.

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Detailed Solution

$Resonance energy = (- 5536 + 5482.32) kJ {mol}^{- 1} = - 53.68 kJ {mol}^{- 1}$

Thus, the resonance energy of benzene is $- 53.68 kJ {mol}^{- 1}$ .

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