Enthalpies of formation of ethane, ethyene and benzene from the gaseous atoms are −2839.2, −2275.2 and −5536 kJ mol−1, respectively. Bond enthalpy of C-H is 410.87 kJ mol−1. Resonance energy of benzene is

Enthalpies of formation of ethane, ethyene and benzene from the gaseous atoms are $- 2839.2$ , $- 2275.2$ and $- 5536 kJ {mol}^{- 1}$ , respectively. Bond enthalpy of C-H is $410.87 kJ {mol}^{- 1}$ . Resonance energy of benzene is

A
$- 243.59 kJ {mol}^{- 1}$
B
$- 156.84 kJ {mol}^{- 1}$
C
$- 23.4 kJ {mol}^{- 1}$
D
$- 53.68 kJ {mol}^{- 1}$

Solution:

$Resonance energy = (- 5536 + 5482.32) kJ {mol}^{- 1} = - 53.68 kJ {mol}^{- 1}$

Thus, the resonance energy of benzene is $- 53.68 kJ {mol}^{- 1}$ .

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