Q.

Ethyl Benzene $\to_{(ii) H^{\pm} / H_{2} O}^{(i) {KMnO}_{4} / {OH}^{-}}$ Predict X in above reaction

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C₆ H₅ CH₂ COOH

C₆ H₅ CH₂ CHO

Benzoic acid

Benzaldehyde

answer is C.

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Detailed Solution

Any alkyl substituted benzene on oxidation with KMnO₄ forms Benzoic acid.

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