Fluorine is more electronegative than nitrogen. The best explanation is that :

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the nitrogen has half filled valence shell electron c.onfiguration, ${ns}^{2} {np}^{3}$ where as fluorine has partially filled electron configuration $n s^{2} n p^{5}$ .

the electronegativity decreases from top to bottom in each of the group as the effective nuclear charge remains constant.

the charge on a F nucleus Is +9, while that on N nucleus is +7

the valency electrons in F are on average, a little farther to the nucleus than in N

answer is B.

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Detailed Solution

The nuclear charge of an atom—more protons equals more "pull" on electrons—and the quantity and distribution of additional electrons within the atomic shells are two factors that affect electronegativity. Electronegativity rises as nuclear charge does. The charge on a F nucleus Is +9, while that on N nucleus is +7. So, Fluorine is more electronegative than nitrogen.

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