For a reaction 2NH3N2+3H2,it is observed that dNH3dt=k1NH3,dN2dt=k2NH3,dH2dt=k3NH3
What is the relation between k1,k2  and  k3?

 

  1. A

    k1=k2=k3

  2. B

    3k1=6k2=2k3

  3. C

    2k1=3k2=6k3

  4. D

    6k1=3k2=2k3

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    Solution:

    2NH3N2+3H212dNH3dt=dN2dt=13dH2dt12×k1NH3=k2NH3=13k3NH33k1=6k2=2k3

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