For a reaction A2(g)+2B2(g)⟶2AB2, ΔrH∘=−100kJmol−1  and  ΔrS∘=−250.0JK−1mol−1. The reaction will be spontaneous

For a reaction A2(g)+2B2(g)2AB2, ΔrH=100kJmol1  and  ΔrS=250.0JK1mol1. The reaction will be spontaneous

  1. A

    provided T=400 K

  2. B

    providedT>400 K

  3. C

    providedT<400 K

  4. D

    providedT>500 K

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    Solution:

    Since ΔrG=ΔrHTΔrS<0 ,we have   ΔrHTΔrS>0  or  ΔrH>TΔΓS or T<ΔrH/ΔrS=100×103Jmol1/250JK1mol1=400 K.

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