For a reaction A→B, it is found that [A]0t1/2 is constant. The order of the reaction with respect to A is

For a reaction $A \to B$ , it is found that $[A]_{0} \sqrt{t_{1 / 2}}$ is constant. The order of the reaction with respect to A is

A
0
B
1
C
2
D
3

Solution:

$t_{1 / 2} \propto 1 / [A]_{0}^{n - 1}$ where n is the order of the reaction. If $n = 3,$ then $t_{1 / 2} \propto 1 / [A]_{0}^{2}$ or $(t_{1 / 2}) {([A]_{0})}^{2} =$ constant

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