For a reversible adiabatic expansion of an ideal gas

For a reversible adiabatic expansion of an ideal gas

  1. A

    ΔS=+ ve 

  2. B

    ΔS= ve 

  3. C

    ΔS=0

  4. D

    may be +ve or -ve depending upon T of the gas

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    Solution:

    For adiabatic reversible expansion, ΔS=0. The entropy change due to volume expansion compensates decrease in entropy during decrease in temperature.

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