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For a reversible adiabatic expansion of an ideal gas

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a
ΔS=+ ve 
b
ΔS= ve 
c
ΔS=0
d
may be +ve or -ve depending upon T of the gas

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detailed solution

Correct option is C

For adiabatic reversible expansion, ΔS=0. The entropy change due to volume expansion compensates decrease in entropy during decrease in temperature.

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