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For complete combustion of ethanol, C2H5OH(l)+3O2(g)CO2(g)+3H2O(l), the heat produced as measured in bomb calorimeter, is  1364.47kJmol1 at 25°C. Assuming ideality the enthlapy of combustion, ΔcH, for the reaction will be R=8.314JK1mol1

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a
1350.50kJmol1
b
1366.95kJmol1
c
1361.95kJmol1
d
1460.50kJmol1

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detailed solution

Correct option is B

For the given reaction, Δvg=1. Hence 

ΔH=ΔU+ΔvgRT=1364.47kJmol1+(1)8.314×103kJK1mol1(298K)=1366.95kJmol1

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