Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

For the decomposition reaction NH2COONH4(s)2NH3(g)+CO2(g),  the Kp=2.9×105atm3. The total pressure of gases at equilibrium when 1.0mol of  NH2COONH4(s) was taken to start with would be

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

0.0194 atm

b

0.0776 atm

c

0.0388 atm

d

0.0582 atm

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

NH2COONH4(s)1.0molx2NH3(g)2p+CO2(g)p

Kp=pNH32pCO2 i.e. 2.9×105atm3=(2p)2p

This gives p=2.9×105atm41/3=0.0194atm and  ptotal =2p+p=3p=3×0.0194atm=0.0582atm

Watch 3-min video & get full concept clarity

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon