For the reaction  5Br−+BrO3−+6H+→3Br2(aq)+3H2O(I) if the rate of disappearance of Br− is 2.5 x 10- 2  mol L-1 s-1the rate of appearance of Br2will be

For the reaction  $5{\mathrm{Br}}^{-}+{\mathrm{BrO}}_{3}^{-}+6{\mathrm{H}}^{+}\to 3{\mathrm{Br}}_{2}\left(\mathrm{aq}\right)+3{\mathrm{H}}_{2}\mathrm{O}\left(\mathrm{I}\right)$ if the rate of disappearance of ${\mathrm{Br}}^{-}$ is the rate of appearance of ${\mathrm{Br}}_{2}$will be

1. A

2. B

3. C

4. D

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Solution:

we have  $-\frac{1}{5}\frac{\mathrm{d}\left[{\mathrm{Br}}^{-}\right]}{\mathrm{d}t}=\frac{1}{3}\frac{\mathrm{d}\left[{\mathrm{Br}}_{2}\right]}{\mathrm{d}t}$

Hence ,$\frac{\mathrm{d}\left[{\mathrm{Br}}_{2}\right]}{\mathrm{d}t}=-\frac{3}{5}\frac{\mathrm{d}\left[{\mathrm{Br}}^{-}\right]}{\mathrm{d}t}=-\frac{3}{5}\left(-2.5×{10}^{-2}{\mathrm{molL}}^{-1}{\mathrm{s}}^{-1}\right)=1.5×{10}^{-2}{\mathrm{molL}}^{-1}{\mathrm{s}}^{-1}$

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