For the reaction N2+3H2→2NH3, the dNH3dt=2×10-4Ms-1 Therefore the – dN2dt is given as

For the reaction $N_{2} + 3 H_{2} \to 2 {NH}_{3},$ the $\frac{d [{NH}_{3}]}{dt} = 2 \times 10^{- 4} {Ms}^{- 1}$ Therefore the - $\frac{d [N_{2}]}{dt}$ is given as

A
$10^{- 4} {Msec}^{- 1}$
B
$10^{4} {Msec}^{- 1}$
C
$10^{- 2} {Msec}^{- 1}$
D
$4 \times 10^{- 4} {Msec}^{- 1}$

Solution:

Rate of formation of ammonia is twice the disappearance of Nitrogen.

Related content

DHBVN Full Form – Dakshin Haryana Bijli Vitran Nigam

KGF Full Form – Kolar Gold Fields

Top Private Engineering Colleges In Delhi

Top Engineering Colleges in Indore

How to Become a Loco Pilot Indian Railway Recruitment 2023, Online Apply

How many countries are there in the world and Country Names List

What Are The Career Options After 12th with PCM?

50 Most powerful Motivational Quotes for students and Kids

Top 10 Google’s Most Searched People in the World 2023-24

List of Neighbouring Countries of India with Boundaries and Name