For the redox reaction $\mathrm{Zn}\left(\mathrm{s}\right)+{\mathrm{Cu}}^{2+}\left(0.1\mathrm{M}\right)\to {\mathrm{Zn}}^{2+}\left(1\mathrm{M}\right)+\mathrm{Cu}\left(\mathrm{s}\right)$  taking place in a cell $\left(E_{\text{cell }}^{\circ }=1,10\mathrm{V}\right)$ the cell potential at 298 $\mathrm{K}$ will be