For the transformation H2Ol,−10∘C→H2Os,−10∘C, the value of ΔStatal =ΔSsys +ΔSsurr has a

For the transformation $H_{2} O (l, - 10^{\circ} C) \to H_{2} O (s, - 10^{\circ} C)$ , the value of $Δ S_{tatal} (= Δ S_{sys} + Δ S_{surr})$ has a

The reaction $H_{2} O (l, - 10^{\circ} C) \to H_{2} O (s, - 10^{\circ} C)$ is an irreversible process.

Hence, $Δ_{lolal} - positive.$

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