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Formality of a solution containing 50g of NaCl in 500 g of a solution and has a density of $0.936 g / {cm}^{3}$ is

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Correct option is B

Weight of NaCl, $w = 50 g$

GFW of $NaCl = 58.5 g$

Weight of solution = 500 g

Density of solution $= d = 0.936 g / {cm}^{3}$

Volume of solution, $V = \frac{mass}{Density}$

$V = \frac{500 g}{0.936 g {.cm}^{- 3}}; since, d = \frac{m}{V}$

Formality of solution is,

$F = \frac{W}{GFW} \times \frac{1000}{V in mL}$

$∴ Formality = \frac{50}{58.5} \times \frac{1000}{500} \times 0.936 = 1.6 F$

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Formality of a solution containing 50g of NaCl in 500 g of a solution and has a density of0.936 g/cm3 is

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Formality of a solution containing 50g of NaCl in 500 g of a solution and has a density of $0.936 g / {cm}^{3}$ is