Given are the following data at 298 K.ΔfH∘H2O,l=−286kJmol−1 ΔfH∘HNO3,1=−174kJmol−1; ΔfH∘N2O5,g=14.5kJmol−1, The ΔrH∘ for the reaction N2O5(g)+H2O(l)⟶2HNO3(l) is
Given are the following data at 298 K. , The for the reaction is
A
-76.5 kJ mol-1
B
76.5 mol-1
C
97.5 kJ mol-1
D
-97.5 kJ mol-1
Solution:
The required reaction is obtained as -Eq.(iii) - Eq. (i) + 2 Eq. (ii) Hence,