Questions
Given following reaction,
In the above reaction 492 L of is obtained at 1 atm and 300 K temperature.
Determine mass of required in nearest whole number (in kg).
detailed solution
Correct option is B
Given following reaction,
Number of moles of NaClO3 = Number of moles of O2
moles of O2 =PV/RT = () = 20
molar mass of NaClO3 = 20 × 106.5 = 2130 g=2.130kg
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detailed solution
Correct answer is 2
Given following reaction,
Number of moles of NaClO3 = Number of moles of O2
moles of O2 =PV/RT = () = 20
molar mass of NaClO3 = 20 × 106.5 = 2130 g=2.130kg
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