Given: E∘Ag+∣Ag=0.799V and E∘Zn2+∣Zn=−0.673V, which of the following is true? - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
${Ag}^{+}$ can be reduced by $H_{2} (g)$
B
Ag can be oxidized by $H^{+}$
C
${Zn}^{2 +}$ can be reduced by $H_{2} (g)$
D
Ag can reduce ${Zn}^{2 +}$

Solution:

Given: $E^{\circ} ({Ag}^{+} ∣ Ag) = 0.799 V$ and $E^{\circ} ({Zn}^{2 +} ∣ Zn) = - 0.673 V$ ,

From the above equation it is observed that more positive potential will constitute positive terminal (i.e. cathode) and the ions will be reduced here. So ${Ag}^{+}$ is reduced by $H_{2}$ gas.

Hence, ${Ag}^{+}$ can be reduced by $H_{2}$

Given: $E^{\circ} ({Ag}^{+} ∣ Ag) = 0.799 V$ and $E^{\circ} ({Zn}^{2 +} ∣ Zn) = - 0.673 V$ , which of the following is true?

Solution:

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