Given: E∘Ag+∣Ag=0.799V and E∘Zn2+∣Zn=−0.673V, which of the following is true?

Given: EAg+Ag=0.799V and EZn2+Zn=0.673V, which of the following is true?

  1. A

     Ag+can be reduced by H2(g)

  2. B

    Ag can be oxidized by H+

  3. C

    Zn2+ can be reduced by H2(g)

  4. D

    Ag can reduce Zn2+

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    Solution:

    Given: EAg+Ag=0.799V and EZn2+Zn=0.673V

    From the above equation it is observed that  more positive potential will constitute positive terminal (i.e. cathode) and the ions will be reduced here. So Ag+ is reduced by H2 gas.

    Hence, Ag+can be reduced by H2

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