# Had three electrons been possible to be placed in an orbital, the block of potassium in the periodic table would be:

1. A

s

2. B

p

3. C

d

4. D

f

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### Solution:

The electronic configuration for this case can be given as,

$1{\mathrm{s}}^{2},2{\mathrm{s}}^{2},2{\mathrm{p}}^{6},3{\mathrm{s}}^{2},3{\mathrm{p}}^{6},4{\mathrm{s}}^{1}$

This electronic configuration considering given conditions can be given as,

$1{s}^{3},2{s}^{3},3{p}^{9},3{s}^{3},3{p}^{1}$
So, the block of potassium in the periodic table would be p.

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