Had three electrons been possible to be placed in an orbital, the block of potassium in the periodic table would be:

The electronic configuration for this case can be given as,

$1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 4 s^{1}$

This electronic configuration considering given conditions can be given as,

$1 s^{3}, 2 s^{3}, 3 p^{9}, 3 s^{3}, 3 p^{1}$
So, the block of potassium in the periodic table would be p.

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