Half-life of a first order reaction is 5 min. The concentration of reactant after 30 min if its initial concentration is 128 mmol L-1 is

Half-life of a first order reaction is 5 min. The concentration of reactant after 30 min if its initial concentration is $128 mmol L^{- 1}$ is

A
$(128 mmol L^{- 1}) / 2^{4}$
B
$(128 mmol L^{- 1}) / 2^{5}$
C
$(128 mmol L^{- 1}) / 2^{6}$
D
$(128 mmol L^{- 1}) / 2^{7}$

Solution:

30 min is equal to six times the half-life of 5 min. Hence, the concentration will be reduced by $2^{6}$ times.

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