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How many primary alcoholic isomers are possible for $C_{5} H_{12} O ?$

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detailed solution

Correct option is D

There are four isomers that has four primary alcohols:

${CH}_{3} - {CH}_{2} - {CH}_{2} - {CH}_{2} - {CH}_{2} - OH {CH}_{3} - CH ({CH}_{3}) - {CH}_{2} - {CH}_{2} - OH {CH}_{3} - {CH}_{2} - CH ({CH}_{3}) - {CH}_{2} - OH {CH}_{3} - C {({CH}_{3})}_{2} - {CH}_{2} - OH$

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detailed solution

Correct answer is 4

There are four isomers that has four primary alcohols:

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How many primary alcoholic isomers are possible for C5H12O ?