Hybridization of iodine atoms in ICl3 (in its stable form, found in solid state) and I2Cl4 Br2 are :

Hybridization of iodine atoms in ${ICl}_{3}$ (in its stable form, found in solid state) and $I_{2} {Cl}_{4} {Br}_{2}$ are :

A
$s p^{3}$ and $s p^{3} d^{2}$
B
$s p^{3} d^{2}$ and $s p^{3} d^{3}$
C
Both $s p^{3} d$
D
Both $s p^{3} d^{2}$

Solution:

Hybridization of iodine atoms in ${ICl}_{3}$ (in its stable form, found in solid state) and $I_{2} {Cl}_{4} {Br}_{2}$ are Both $s p^{3} d^{2}$ .

Hence, the option D is correct.

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