If the density of a solution containing 217 .0 g ethylene glycol ( C2H6O2 ) in 200 g water is 1.10 g cm-3 the molarity of the solution is

If the density of a solution containing 217 .0 g ethylene glycol ( C₂H₆O₂ ) in 200 g water is 1.10 g cm^-3 the molarity of the solution is

A
8.8 mol dm^-3
B
10.1 mol dm^-3
C
9.23 mol dm^-3
D
12.12 mol dm^-3

Solution:

Total mass of solution, m = 417 .0 g

Volume of solution $V = \frac{m}{ρ} = \frac{417.0 g}{1.10 g {cm}^{- 3}} = 379.1 {cm}^{3}$

Amount of C₂H₆ O2 $n = \frac{m}{M} = \frac{217.0 g}{62 g {mol}^{- 1}} = 3.5 mol$

Molarity of solution $M = \frac{n}{V} = \frac{3.5 mol}{379.1 \times 10^{- 3} {dm}^{3}} = 9.23 mol {dm}^{- 3}$

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