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If the principal quantum number is n = 6, the correct sequence of filling of electrons will be :

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a
ns(n1)d(n2)fnp
b
nsnp(n1)d(n2)f
c
ns(n2)f(n1)dnp
d
ns(n2)fnp(n1)d

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detailed solution

Correct option is C

If the fundamental quantum number is 6, the proper order for filling one electron will be ns(n2)f(n1)dnp
Here, n=6. Therefore, the proper order of electron filling will be 6s4f5d6p.

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