Search for: If ΔfH∘C2H6=−84kJmol−1,Δsub H∘C, graphite )=720kJmol−1,ΔatH2=435kJmol−1 and the bond enthalpy εC−H=414kJmol−1 then the bond enthalpy εC−C will be aboutIf ΔfH∘C2H6=−84kJmol−1,Δsub H∘C, graphite )=720kJmol−1,ΔatH2=435kJmol−1 and the bond enthalpy εC−H=414kJmol−1 then the bond enthalpy εC−C will be aboutA295 kJ mol-1B315 kJ mol-1C345 kJ mol-1D375 kJ mol-1 Register to Get Free Mock Test and Study Material Grade ---Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pmPlease indicate your interest Live ClassesRecorded ClassesTest SeriesSelf LearningVerify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:According to Hess's lawΔfH∘=2Δsub H∘(C)+3ΔatH∘H2−εC−C−6εC−H εC−C=2ΔsubH∘(C)+3ΔatH∘H2−6εC−H−ΔfH∘=[2×720+3×435−6×414+84]kJmol−1=345kJmol−1Related content Distance Speed Time Formula Refractive Index Formula Mass Formula Electric Current Formula Ohm’s Law Formula Wavelength Formula Electric Power Formula Resistivity Formula Weight Formula Linear Momentum Formula