If ΔH1=900kJ

ΔH2=650kJ

Then find ΔHeg of X.

  1. A

    250kJ

  2. B

    1550kJ

  3. C

    250kJ

  4. D

    +1550kJ

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    Solution:

    Given,

    ΔH1=900kJ

    ΔH2=650kJ

    The change in the enthalpy is

    ΔH=ΔH2ΔH1

    .ΔH=900-650

    ΔH=250 kJ

    Hence, ΔHeg of Xis 250 kJ.

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