If $Δ H_{1} = 900 kJ$
$Δ H_{2} = 650 kJ$
Then find $Δ H_{e g}$ of $X$ .

A
$- 250 k J$
B
$- 1550 kJ$
C
$250 kJ$
D
$+ 1550 kJ$

Solution:

Given,

$Δ H_{1} = 900 kJ$

$Δ H_{2} = 650 kJ$

The change in the enthalpy is

$Δ H = Δ H_{2} - Δ H_{1}$

. $Δ H = 900 - 650$

$Δ H = 250 kJ$

Hence, $Δ H_{e g}$ of $X$ is 250 kJ.

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