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Q.

If $z -$ axis be the internuclear axis, which of the following combination of orbitals would not form $π -$ bond?

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a

$d_{2 x} + d_{2 x}$

b

$d_{y z} + d_{y z}$

c

$p_{x} + p_{x}$

d

$d_{x y} + d_{x y}$

answer is B.

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Detailed Solution

$d_{x y} - d_{x y}$ form $π -$ bond if $z -$ axis is the internuclear axis.

Atomic orbitals connect in a sideways positive (same phase), perpendicular to the internuclear axis direction, to generate pi bonds.

Hence, the option B is correct.

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If z-axis be the internuclear axis, which of the following combination of orbitals would not form π-bond?