In a system A(s)⇌B(g)+2C(g) doubling the equilibrium concentration of B will cause the equilibrium concentration of C to change to

In a system $A (s) ⇌ B (g) + 2 C (g)$ doubling the equilibrium concentration of B will cause the equilibrium concentration of C to change to

A
two times its original value
B
one-half its original value
C
$\sqrt{2}$ times the original value
D
$1 / \sqrt{2}$ times the original value

Solution:

$[B]_{1} [C]_{1}^{2} = [B]_{2} [C]_{2}^{2}$

It is given that $[B]_{2} = 2 [B]_{1} .$ Hence $[C]_{2} = \frac{[C]_{1}}{\sqrt{2}}$

Related content

Download JEE Advanced 2023 Answer Key with Detailed Video Solutions

NCERT Books for Class 12- Download Free PDF (2023-2024)

NCERT Books for Class 6 to 12 – Download Free PDF Updated for 2023-24

Learning Beyond Boundaries: Rohit Sharma’s Vision for Accessible Education

Rohit Sharma: The Cricketer, The Icon – A Biography

ORS Full Form – Oral Rehydration Solution

SDO Full Form – Sub Divisional Officer

ESI Full Form – Employee State Insurance

NEET 2023 Result Date: Check Result, Download NEET UG Result PDF

ESIC Full Form – Employees’ State Insurance Corporation