In the chemical reaction, CH3CH2NH2+CHCl3+3KOH⟶(A)+(B)+3H2O and the compounds (A) and (B) respectively are:

In the chemical reaction, ${CH}_{3} {CH}_{2} {NH}_{2} + {CHCl}_{3} + 3 KOH ⟶ (A) + (B) + 3 H_{2} O$ and the compounds (A) and (B) respectively are:

A
$C_{2} H_{5} CN$ and $3 KCl$
B
${CH}_{3} {CH}_{2} {CONH}_{2}$ and $3 KCl$
C
$C_{2} H_{5} NC$ and $K_{2} {CO}_{3}$
D
$C_{2} H_{5} NC$ and $3 KCl$

Solution:

The involved reaction is ${CH}_{3} {CH}_{2} {NH}_{2} + {CHCl}_{3} + 3 KOH \to C_{2} H_{5} NC + 3 KCl + 3 H_{2} O$

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