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In the system $AB (s) ⇌ A (g) + B (g)$ doubling the equilibrium concentration of A will cause the equilibrium concentration of B to

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change to two times its original value

change to one-half its original value

remain constant

change to a new value which cannot be predicted

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detailed solution

Correct option is B

$K_{eq} = p_{A} p_{B}$

If $p_{A}$ becomes double, $p_{B}$ will become half since only then $p_{A} p_{B}$ will be constant.

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In the system AB(s)⇌A(g)+B(g) doubling the equilibrium concentration of A will cause the equilibrium concentration of B to