In view of the signs ΔrG∘ of for the following reactionsPbO2+Pb→2PbO;    ΔtG∘<0SnO2+Sn→2SnO;    ΔTG∘>0Which oxidation states are more characteristic for lead and tin?

# In view of the signs ${\mathrm{\Delta }}_{r}{G}^{\circ }$ of for the following reactions$\begin{array}{l}{\mathrm{PbO}}_{2}+\mathrm{Pb}\to 2\mathrm{PbO}; {\mathrm{\Delta }}_{t}{G}^{\circ }<0\\ {\mathrm{SnO}}_{2}+\mathrm{Sn}\to 2\mathrm{SnO}; {\mathrm{\Delta }}_{T}{G}^{\circ }>0\end{array}$Which oxidation states are more characteristic for lead and tin?

1. A

For lead +4, for tin +2

2. B

For lead +2, for tin +2

3. C

For lead +4, for tin +4

4. D

For lead +2, for tin +4

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### Solution:

${\mathrm{\Delta }}_{r}{G}^{\circ }<0$ implies that the reaction is feasible. Thus, the more characteristic oxidation state oflead is +2.

${\mathrm{\Delta }}_{r}{G}^{\circ }\mathit{>}0$ implies that the reaction is not feasible. Thus, the more characteristic oxidation state of tin is +4.  