In which of the following change both the electrons are removed from same orbital?

The following change both the electrons are removed from same orbital are,

$\begin{array}{l}{ }_{29}{\mathrm{Cu}}_{ }\to [\mathrm{Ar}] 3{\mathrm{d}}^{10}4{\mathrm{s}}^1\\ { }_{24}\mathrm{Cr}\to \left[\mathrm{Ar}\right]3{\mathrm{d}}^{5}4{\mathrm{s}}^1\\ { }_{32}\mathrm{Ge}\to \left[\mathrm{Ar}\right]3{\mathrm{d}}^{10}4{\mathrm{s}}^2\\ { }_{30}\mathrm{Zn}\to \left[\mathrm{Ar}\right]3{\mathrm{d}}^{10}4{\mathrm{s}}^2\end{array}$

The electrons are removed from same orbital in the ${ }_{30}\mathrm{Zn}$.

Hence option D is correct.