Questions

Ionization energies of three hypothetical elements given below (in kJ/mole)
I II III
X 122 340 1890
Y 99 931 1100
Z 118 1220 1652
Energy (in kJ/mole) required for the process $Z \to$ $Z^{2 +} + 2 e^{-}$ will be:

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detailed solution

Correct option is C

Energy (in kJ/mole) required for the process $Z \to$ $Z^{2 +} + 2 e^{-}$ will be: 1338

$E = 118 + 1220 = 1338$

Hence, option C is correct

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Ionization energies of three hypothetical elements given below (in kJ/mole) IIIIIIX1223401890Y999311100Z11812201652Energy (in kJ/mole) required for the process Z→ Z2++2e− will be: