It is desired to change pH of 0.05 M acetic acid solution to 1.5 times pH value, the solution should be diluted to

It is desired to change pH of 0.05 M acetic acid solution to 1.5 times pH value, the solution should be diluted to

A
540.5
B
870.5
C
1033.3
D
1150.0

Solution:

$pH = 1.5 \times 3.02 = 4.53$

$[H^{+}] - (10^{- pH}) M - 2.95 \times 10^{- 5} M$

$c - {[H^{+}]}^{2} / K_{a} - {(2.95 \times 10^{- 5} M)}^{2} / (1.8 \times 10^{- 5} M) - 4.84 \times 10^{- 5} M$

Dilution factor $= \frac{0.05 M}{4.84 \times 10^{- 5} M} = 1033.3$

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