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Number of electrons having the quantum numbers
$n = 4, l = 0, s = - \frac{1}{2}$ in ${Zn}^{+ 2} ion$ is / are

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detailed solution

Correct option is B

${Zn}^{2 +}$ has no use $4 s e^{-}$ .

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10}$

Since it is Zn2+, it has lost 2 electrons since the previous shell.

Hence, it will be $4 s^{0}$ instead of $4 s^{2}$

Thus, the number of electrons having the quantum numbers is 0.

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Number of electrons having the quantum numbersn=4,l=0,s=−12in Zn+2 ion is / are