Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Pure Benzene freezes at 5.4 °C. A solution of0.223 g of phenyl acetic acid C6H5CH2COOH in 4.4 g of benzene Kf=5.12 K kg mol-1 freezes at 4.47 °C. From this observation, one can conclude that

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

phenyl acetic acid undergoes complete ionization in benzene

b

phenyl acetic acid dimerizes in benzene.

c

phenyl acetic acid exists as such in benzene

d

phenyl acetic acid undergoes partial ionization in benzene

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

m=-ΔTfKf=(5.4-4.47)5.12 mol kg-1 i.e. 0.223 g/M(4.4/1000)kg=0.935.12 mol kg-1

Solving for M, we get M=279 g mol-1

Number of molecules of phenyl acetic acid =279136=2

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon