${sp}^{3}$ hybridisation is seen in

A
${NH}_{3}$
B
$H_{2} O$
C
$C_{2} H_{4}$
D
$HCHO$

Solution:

Both

{NH}_{3}

and

H_{2} O

will undergo

{sp}^{3}

hybridisation based on the formation of bonds with unhybridised orbitals of hydrogen atoms.

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