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Stability of species ${Li}_{2}, {Li}_{2}^{-}$ and ${Li}_{2}^{+}$ increases in the order of:

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a

{Li}_{2} < {Li}_{2}^{+} < {Li}_{2}

b

{Li}_{2} < {Li}_{2} < {Li}_{2}^{+}

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detailed solution

Correct option is B

The electronic configuration of' ${Li}_{2}, {Li}_{2}^{+}, {Li}_{2}^{-}$ and their bond orders are

$\underset{Bond order = 1}{{Li}_{2} (σ 2 s)^{2}} \underset{Bond order = 1 / 2}{{Li}_{2}^{+} (σ 2 s)^{1}} \underset{Bond order = 1 / 2}{{Li}_{2}^{-} (σ 2 s)^{2} (σ * 2 s)^{1}}$

The species ${Li}_{2}$ will have larger electronic repulsion as compared to ${Li}_{2}^{+}$ and thus will be less stable. Thus, the stability order is ${Li}_{2} < {Li}_{2}^{+} < {Li}_{2}^{-}$

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