Structure of Na2B4O5(OH)4⋅8H2O contains:

Structure of ${Na}_{2} [B_{4} O_{5} (OH)_{4}] \cdot 8 H_{2} O$ contains:

A
two triangular and two tetrahedral units of boron
B
three triangular and one tetrahedral units of boron
C
all tetrahedral units of boron
D
all triangular units of boron

Solution:

Zero $π$ bonds.

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