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The normality of $1 {M H}_{3} {PO}_{3}$ solution is

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detailed solution

Correct option is C

The relation between normality (N) and molarity (M) as follows below.

$N = n × M$

Here, n is basicity of an acid. For $H_{3} {PO}_{3}$ , $n = 2$

Because there are only 2 “H atoms” can replaceable in $H_{3} {PO}_{3}$ .

Concentration of $H_{3} {PO}_{3}$ ,M $=1M$

Therefore, $normality = 2 \times 1 = 2 N$

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The normality of 1M H3PO3 solution is