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The vapor pressure of a solution at $100 ° C$ containing 3g of cane sugar in 33g of water (vapor pressure of water at $100 ° C = 760 mm$ of Hg) is

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756.36 mm of Hg

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detailed solution

Correct option is A

Weight of cane sugar $w = 3 g$

Molar mass of cane sugar, $M .W = 342 g/mol$

Weight of water (solvent), $W = 33 g$

Vapor pressure of pure solvent (water),

$P ° = 760 mm of Hg$

Vapor pressure of solution, $P = x$

From the Raoult’s law,

$\frac{P ° - P}{P °} = \frac{w}{m} \times \frac{M}{W}$

$\frac{760 - x}{760} = \frac{3}{342} \times \frac{18}{33}$

$761 - x = \frac{760}{19 \times 11} = 3.63$

$x = 760 - 3.63$

$∴ Vapour pressure of solution, x = 756.36 mm of Hg$

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The vapor pressure of a solution at 100°C containing 3g of cane sugar in 33g of water (vapor pressure of water at 100°C=760 mm of Hg) is