The boiling point of $10\mathrm{\%}\left(\mathrm{w}/\mathrm{w}\right)$ solution of urea in water (For water  ${\mathrm{k}}_{\mathrm{b}}=0.52\text{\hspace{0.17em}K\hspace{0.17em}\hspace{0.17em}}\mathrm{kg}/\mathrm{mol}$

$\begin{array}{l}{\mathrm{\Delta T}}_{\mathrm{b}}={\mathrm{k}}_{\mathrm{b}}\cdot \mathrm{m}\\ =0.52\times \frac{10\times 1000}{60\times 90}=0.{963}^{\circ }\mathrm{C}\\ \mathrm{B}\cdot \mathrm{pt}={\left(100+{\mathrm{\Delta T}}_{\mathrm{b}}\right)}^{\circ }\mathrm{C}\\ ={(100+0.963)}^{\circ }\mathrm{C}\\ =100.{963}^{\circ }\mathrm{C}\end{array}$