The bond angle H - X - H is the greatest in the compound:

A
${PH}_{3}$
B
${CH}_{4}$
C
${NH}_{3}$
D
$H_{2} O$

Solution:

${CH}_{4}$ has the greatest $H - C - H$ bond angle. The other molecules have lone pair(s) of electrons. Due to lone pair-bonding pair repulsion, the angle $H - X - H$ is decreased from the expected bond angle of tetrahedral structure. i.e. $109 ° 28' .$

The bond angle $H - X - H$ is the greatest in the compound:

Solution:

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