Solution:
In case of isoelectronic species, Ionic radius increases as -ve charge(no. of electrons) increases and +ve charge(nuclear charge) decreases.
Hence, O2– > F– > Na+ > Mg2+ > Al3+
The correct sequence which shows decreasing order of the ionic radii of the elements is
In case of isoelectronic species, Ionic radius increases as -ve charge(no. of electrons) increases and +ve charge(nuclear charge) decreases.
Hence, O2– > F– > Na+ > Mg2+ > Al3+